If it's not what You are looking for type in the equation solver your own equation and let us solve it.
0.35x^2+5.3x=0
a = 0.35; b = 5.3; c = 0;
Δ = b2-4ac
Δ = 5.32-4·0.35·0
Δ = 28.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.3)-\sqrt{28.09}}{2*0.35}=\frac{-5.3-\sqrt{28.09}}{0.7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.3)+\sqrt{28.09}}{2*0.35}=\frac{-5.3+\sqrt{28.09}}{0.7} $
| 0.35x^2-5.3x=0 | | 2y-8×=20 | | 2x^2-12x+31=x^2 | | 25-3x=36 | | (5x^2+3x)+(3x^2+5x)= | | 7x-9x2=5x=-6 | | -13=12-x/4 | | 7x-9x2=5=-6 | | 6|7r|−5=4 | | (1/4)x+x=150 | | 492y+1=7y+8492y+1=7y+8. | | 4(3a-5)=5a+4 | | 4–2x+7=32x–8 | | X+3/4y=41 | | 2.7.b=54 | | 27+3(5x-7)=47 | | -5x-9=-0 | | 3.q-145.5=5q | | w-4.48=3.31 | | 6(z+3)–9=27 | | 3x-1=-37 | | x+3.1=9.83 | | -2b^2+5b=0 | | 4y-1=3(-5-7) | | (5k+3)^2=27 | | (5k+3)^3=27 | | f(-4)=-2-5 | | -13=12(x/4) | | 5y-8+y+52=6y+50-2y | | 51+(8x+1)=90 | | 3q^2-5q-6=3q^2 | | -13=12x/4 |